A) Bulb 1 will glow more first and then its brightness will become less than bulb 2
B) Bulbl
C) Bulb2
D) Both glow equally
Correct Answer: B
Solution :
Total resistance \[=\frac{6\times 3}{6+3}=2\Omega \] Current in circuit \[=\frac{6}{2}=3A\] Therefore current through bulb 1 is 2A and bulb 2 is 1A So bulb 1 will glow moreYou need to login to perform this action.
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