A) \[x+2y=0\]
B) \[x+y=2\]
C) \[x-2y=0\]
D) \[x+y=6\]
Correct Answer: D
Solution :
\[{{x}^{2}}=8y\] ...(i) When, x = 4, then y = 2 Now\[{{\left. \frac{dy}{dx}=\frac{2x}{8}=\frac{x}{4},\frac{dy}{dx} \right]}_{x=4}}=1\] Slope of normal \[=-\frac{1}{\frac{dy}{dx}}=-1\] Euqation of normal at x = 4 is \[y=-2=-1(x-4)\] \[\Rightarrow \]\[y=-x+4+2=-x+6\] \[\Rightarrow \]\[x+y=6\]You need to login to perform this action.
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