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JEE Main & Advanced JEE Main Paper (Held On 25 April 2013)

  • question_answer
    Give               (A) \[n=5,\,\,{{m}_{l}}=+1\]                (B) \[n=2,\,\,l+1,\,\,\,{{m}_{l}}=-1\],\[{{\operatorname{m}}_{s}}=-1/2\]     JEE Main Online Paper ( Held On 25  April 2013 )

    A) 25 and 1                              

    B) 8 and 1

    C) 2 and 4                          

    D) 4 and  1

    Correct Answer: B

    Solution :

    (i) n= 5 means l-0,1,2,3,4 since m =+ 1 hence total no. of electrons will be = 0 (from s) + 2 (from p) + 2 (from d) + 2 (from f) + 2 (from g) =0+2+2+2+2=8 (ii)\[n=2,l=1,{{m}_{l}}=-1,{{m}_{s}}=-1/2\]represent 2p orbital with one electron


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