A) \[4x+3y+5=0\]
B) \[3x+4y+3=0\]
C) \[4x+3y+3=0\]
D) \[3x+4y+5=0\]
Correct Answer: B
Solution :
Let \[C=({{x}_{1}},{{y}_{1}})\] Centroid,\[E=\left( \frac{{{x}_{1}}-5}{3},\frac{{{y}_{1}}+3}{3} \right)\] Since centroid lies on the line \[3x+4y+2=0\] \[\therefore \]\[3\left( \frac{{{x}_{1}}+5}{3} \right)+4\left( \frac{{{y}_{1}}+3}{3} \right)+2=0\] \[\Rightarrow \]\[3{{x}_{1}}+4{{y}_{1}}+3=0\] Hence vertex \[({{x}_{1}},{{y}_{1}})\]lies on the line \[3x+4y+3=0\]You need to login to perform this action.
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