A) Zero
B) 1
C) \[\frac{144}{25}\]
D) \[\frac{25}{144}\]
Correct Answer: B
Solution :
From question, \[{{E}_{x}}=5N/kg\]and\[{{E}_{y}}=12N/kg\] Gravitational potential = Gravitational field \[\times \]distance \[\therefore \]\[{{V}_{(12m,0)}}={{E}_{x}}\times 12J/kg\] and\[{{V}_{(0,5m)}}={{E}_{y}}\times 5J/kg\] (Given: potential at the origin is zero) \[\therefore \]\[\frac{{{V}_{(12m,0)}}}{{{V}_{(0,5m)}}}=\frac{{{E}_{x}}\times 12}{{{E}_{y}}\times 5}=\frac{5\times 12}{12\times 5}=1\]You need to login to perform this action.
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