A) -88 Kj
B) -66 Kj
C) -62 Kj
D) -44 Kj
Correct Answer: A
Solution :
\[{{N}_{2}}(g)+\frac{1}{2}{{O}_{2}}\to {{N}_{2}}O(g)\] \[N\equiv N(g)+\frac{1}{2}\left( O=O \right)\to N=\overset{+}{\mathop{N}}\,=O(g)\] \[\Delta H_{f}^{o}=\][Energy required for breaking of bonds] -[Energy released for forming of bonds] \[=(\Delta {{H}_{N\equiv N}}+\frac{1}{2}\Delta {{H}_{O=O}}-(\Delta {{H}_{N=N}}+\Delta {{H}_{N=O}})\] \[=(946+\frac{1}{2}\times 498)-(418+607)=170kJ\,mo{{l}^{-1}}\] Resonance energy \[=170-82=88kJ\,mo{{l}^{-1}}\]You need to login to perform this action.
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