JEE Main & Advanced JEE Main Paper (Held On 25 April 2013)

  • question_answer
                    Let \[f(1)=-2\] and \[f'(x)\ge 4.2\] for 1 \[\le x\le 6.\]The possible value of \[f(6)\] lies in the interval     JEE Main Online Paper ( Held On 25  April 2013 )

    A)                 \[\left( 15,19 \right)\]                   

    B)                                        \[\left( -\infty ,12 \right)\]

    C)                                        \[[12,\,15)\]                      

    D)                                        \[[19,\,\infty )\]

    Correct Answer: D

    Solution :

                    Given\[f(1)=-2\]and\[f'(x)\ge 4.2\]for Consider\[f'(x)=\frac{f(x+h)-f(x)}{h}\] \[\Rightarrow \]\[f(x+h)-f(x)=f'(x).h\ge (4.2)h\] So,\[f(x+h)\ge f(x)+(4.2)h\] Put x = 1 and h = 5, we get \[f(6)\ge f(1)+5(4.2)\Rightarrow f(6)\ge 19\] Hence f (6) lies in\[[19,\infty )\]  


You need to login to perform this action.
You will be redirected in 3 sec spinner