A) r+s-1
B) r+s-2
C) r+s+1
D) r+s
Correct Answer: D
Solution :
Given:\[\frac{{{a}_{p}}+{{a}_{q}}}{2}=\frac{{{a}_{r}}+{{a}_{s}}}{2}\] \[\Rightarrow \]\[a+(p-1)d+a+(q-1)d\] \[=a+(r-1)d+a+(s-1)d\] \[\Rightarrow \]\[2a+(p+q)-2d=2a+(r+s)d-2d\] \[\Rightarrow \]\[(p+q)d=(r+s)d\Rightarrow p+q=r+s.\]You need to login to perform this action.
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