A) \[1.40\times {{10}^{-9}}\]
B) \[0.14\times {{10}^{-9}}\]
C) \[140\times {{10}^{-9}}\]
D) \[14.0\times {{10}^{-9}}\]
Correct Answer: D
Solution :
\[\underset{s}{\mathop{Pb}}\,\underset{2s}{\mathop{{{I}_{2}}}}\,P{{b}^{++}}+2{{I}^{-}}\] \[{{K}_{sp}}=s\times {{(2s)}^{2}}=4{{s}^{3}}\] \[=4\times \left( \frac{0.7}{461.2} \right)=14.0\times {{10}^{-9}}\]You need to login to perform this action.
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