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JEE Main & Advanced JEE Main Paper (Held On 26 May 2012)

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    The line parallel to x-axis and passing through the point of intersection of lines \[ax+2by+3b=0\]and \[bx-2ay-3a=0,\] where \[(a,b)\ne (0,0)\] is.   JEE Main Online Paper (Held On 26-May-2012)  

    A) above x-oxis ata distance 2/3 from it

    B)                        above x-axis at a distance 3/2 from it

    C)                        below x-axis at a distance 3/2 from it                

    D)                        below x-axis at a distance 2/3 from it

    Correct Answer: C

    Solution :

                    Given lines are\[ax+2by+3b=0\]and\[bx-2ay-3a=0\] Since, required line is || to x-axis \[\therefore \]\[x=0\] We put x = 0 in given equation, we ge \[2by=-3b\Rightarrow y=-\frac{3}{2}\] This shows that the required line is below x-axis at a distance of \[\frac{3}{2}\]from it.


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