A) \[{{x}^{2}}+{{y}^{2}}+2x=2y+11=0\]
B) \[{{x}^{2}}+{{y}^{2}}-2x+2y-7=0\]
C) \[{{x}^{2}}+{{y}^{2}}-2x-2y-3=0\]
D) \[{{x}^{2}}+{{y}^{2}}+2x+2y-11=0\]
Correct Answer: D
Solution :
Point (1,2) lies on the circle \[{{x}^{2}}+{{y}^{2}}+2x+2y\]\[-11=0,\] because coordinates of point (1,2) satisfy the equation\[{{x}^{2}}+{{y}^{2}}+2x+2y-11=0\] Now,\[{{x}^{2}}+{{y}^{2}}-4x-6y-21=0\] ?(i) \[{{x}^{2}}+{{y}^{2}}+2x+2y-11=0\] ?(ii) \[3x+4y+5=0\] ?(iii) From (i) and (iii), \[{{x}^{2}}+{{\left( -\frac{3x+5}{4} \right)}^{2}}-4x-6\left( \frac{3x+5}{4} \right)-21=0\] \[\Rightarrow \]You need to login to perform this action.
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