A) \[\frac{\ell }{\sqrt{2\pi }}\]
B) \[\frac{\ell }{\sqrt{3\pi }}\]
C) \[\frac{\ell }{3\pi }\]
D) \[\frac{\ell }{2\pi }\]
Correct Answer: A
Solution :
As\[{{A}_{1}}{{v}_{1}}={{A}_{2}}{{v}_{2}}\](Principle of continuity) or,\[{{\ell }^{2}}\sqrt{2gh}=\pi {{r}^{2}}\sqrt{2g\times 4h}\] (Efflux velocity \[=\sqrt{2gh}\] ) \[\therefore \]\[{{r}^{2}}=\frac{{{\ell }^{2}}}{2\pi }\]or\[r=\sqrt{\frac{{{\ell }^{2}}}{2\pi }}=\frac{{{\ell }^{2}}}{\sqrt{2\pi }}\]You need to login to perform this action.
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