A) 4.8kcal
B) 7.2kcal
C) 8.2 kcal
D) 2.4 kcal
Correct Answer: D
Solution :
Number of moles \[=\frac{1}{35.5}\] Given, 1 eV = 23.06 kcal \[\text{mo}{{\text{l}}^{\text{-1}}}\] eV = 3.7 x 23.06 kcal \[\text{mo}{{\text{l}}^{\text{-1}}}\] i.e. 1 mole realease energy \[=3.7\times 23.06\] kcal \[\therefore \]Energy released . \[=\frac{1}{35.5}\times 3.7\times 23.06\,\text{kcal}=2.4\,\text{kcal}\]You need to login to perform this action.
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