A) \[\frac{4}{3}\]
B) \[\frac{1}{3}\]
C) \[\frac{3}{3}\]
D) \[\frac{2}{3}\]
Correct Answer: C
Solution :
Reduction half reaction : \[C{{r}_{2}}O_{7}^{2-}+6{{e}^{-}}+14{{H}^{+}}\xrightarrow[{}]{{}}2C{{r}^{3+}}+7{{H}_{2}}O\] Oxidation half reaction : \[Cr\xrightarrow[{}]{{}}C{{r}^{3+}}+3{{e}^{-}}\]Overall reaction : \[C{{r}_{2}}O_{7}^{2-}+Cr+14{{H}^{+}}+3{{e}^{-}}\xrightarrow[{}]{{}}3C{{r}^{3+}}+7{{H}_{2}}O\] 3F of electricity = 3 moles of\[C{{r}^{3+}}\] 1F of electricity\[=\frac{3}{2}\] moles of \[C{{r}^{3+}}\]You need to login to perform this action.
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