A) \[m+n\]
B) \[n-m\]
C) \[\frac{1}{{{2}^{\left(m+n \right)}}}\]
D) \[{{2}^{\left( n-m \right)}}\]
Correct Answer: D
Solution :
Rate\[_{1}=k{{[A]}^{n}}{{[B]}^{m}}\] Rate\[_{2}=k{{[2A]}^{n}}{{\left[ \frac{1}{2}B \right]}^{m}}\] \[\therefore \]\[\frac{\text{Rat}{{\text{e}}_{2}}}{\text{Rat}{{\text{e}}_{1}}}=\frac{k{{[2A]}^{n}}{{\left[ \frac{1}{2}B \right]}^{m}}}{k{{[A]}^{n}}{{[B]}^{m}}}={{(2)}^{n}}{{\left( \frac{1}{2} \right)}^{m}}\] \[={{2}^{n}}.{{(2)}^{-m}}={{2}^{n-m}}\]You need to login to perform this action.
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