A) \[m{{(2m+1)}^{2}}\]
B) \[{{m}^{2}}(m+2)\]
C) \[{{m}^{2}}(2m+1)\]
D) \[m{{(m+2)}^{2}}\]
Correct Answer: A
Solution :
The sum of the given series \[{{1}^{2}}+{{2.2}^{2}}+{{3}^{2}}+{{2.4}^{2}}+{{5}^{2}}+{{2.6}^{2}}+\]??\[+2{{(2m)}^{2}}\]is \[\frac{2m{{(2m+1)}^{2}}}{2}=m{{\left( 2m+1 \right)}^{2}}\]You need to login to perform this action.
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