JEE Main & Advanced JEE Main Paper (Held On 8 April 2017)

  • question_answer
    According to Bohr's theory, the time averaged magnetic field at the centre (i.e. nucleus) of a hydrogen atom due to the motion of electrons in the \[{{\text{n}}^{\text{th}}}\] orbit is proportional to : (n = principal quantum number) [JEE Online 08-04-2017]

    A) \[{{\text{n}}^{-3}}\]                                       

    B) \[{{\text{n}}^{-2}}\]

    C) \[{{\text{n}}^{-4}}\]                                       

    D) \[{{\text{n}}^{-5}}\]

    Correct Answer: B

    Solution :

    \[B=\frac{{{\mu }_{0}}I}{2r}\] \[=\frac{{{\mu }_{0}}qt}{2r}\] \[r\propto {{n}^{2}}\] \[B\propto {{m}^{-2}}\]


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