A) (-2,-7)
B) (8, 5)
C) (-4,-9)
D) \[\left( 4,\frac{1}{3} \right)\]
Correct Answer: A
Solution :
\[{{x}^{2}}{{y}^{2}}-2x=4-4y\] \[2x{{y}^{2}}+2y.{{x}^{2}}.\frac{dy}{dx}-2=-4.\frac{dy}{dx}\] \[\frac{dy}{dx}(2y.{{x}^{2}}+4)=2-2x.{{y}^{2}}\] \[{{\left. \frac{dy}{dx} \right|}_{2,-2}}=\frac{2-2\times 2\times 4}{2(-2)\times 4+4}=\frac{+14}{+12}=\frac{7}{6}\] \[(y+2)=\frac{7}{6}(x-2)\Rightarrow 7x-6y=26\]You need to login to perform this action.
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