A) 3
B) 1
C) 2
D) 0
Correct Answer: B
Solution :
\[\Delta =0\] \[\left| \begin{matrix} 2 & 4 & -\lambda \\ 4 & \lambda & z \\ \lambda & z & 2 \\ \end{matrix} \right|\begin{matrix} 2 & 4 \\ 4 & \lambda =0 \\ \lambda & z \\ \end{matrix}\] \[=-(32+8-{{\lambda }^{3}})=0\] \[=\lambda 3+4\lambda -40=0\]You need to login to perform this action.
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