A) 2 Hz
B) \[\frac{1}{4}Hz\]
C) \[\frac{1}{2\sqrt{2}}Hz\]
D) \[\frac{1}{2}Hz\]
Correct Answer: D
Solution :
\[F=\frac{1}{2\pi }\sqrt{\frac{k}{m}}=1\]\[4{{\pi }^{2}}=\frac{k}{m}m=1\] \[k=4{{\pi }^{2}}\]In parallel \[{{k}_{eq}}=2k\] \[F=\frac{1}{2\pi }\sqrt{\frac{K\times 2}{8}}\] \[=\frac{1}{2}Hz\]You need to login to perform this action.
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