A) 32 mm
B) 16 mm
C) 28 mm
D) 20 mm
Correct Answer: B
Solution :
Energy of sphere\[=\frac{{{Q}^{2}}}{2C}\] \[4.5=\frac{16\times {{10}^{-12}}}{2C}\] \[C=\frac{16\times {{10}^{-12}}}{9}=4\pi {{\varepsilon }_{0}}R\] \[R=\frac{16\times {{10}^{-12}}}{9}\times \frac{1}{4\pi {{\varepsilon }_{0}}}\] \[=9\times {{10}^{9}}\times \frac{16}{9}\times {{10}^{-12}}\] \[=16\times {{10}^{-3}}=16mm\]You need to login to perform this action.
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