A) \[\pi {{\mu }_{0}}{{I}_{0}}\frac{{{a}^{2}}}{b}\omega \sin (\omega t)\]
B) \[\frac{\pi {{\mu }_{0}}{{I}_{0}}}{2}.\frac{{{a}^{2}}}{b}\omega \cos (\omega t)\]
C) \[\frac{\pi {{\mu }_{0}}{{I}_{0}}{{b}^{2}}}{a}\omega \cos (\omega t)\]
D) \[\frac{\pi {{\mu }_{0}}{{I}_{0}}}{2}.\frac{{{a}^{2}}}{b}\omega \sin (\omega t)\]
Correct Answer: D
Solution :
e = MdI dT \[M=\frac{\pi {{\mu }_{0}}{{a}^{2}}}{2b}\] \[=\frac{\pi {{\mu }_{0}}{{a}^{2}}}{2b}=\omega {{I}_{0}}l\omega t\]You need to login to perform this action.
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