A) \[{{\tan }^{-1}}(\sin {{\theta }_{C}})\]
B) \[\frac{1}{{{\tan }^{-1}}(\sin {{\theta }_{C}})}\]
C) \[{{\cos }^{-1}}(\sin {{\theta }_{C}})\]
D) \[\frac{1}{{{\cos }^{-1}}(\sin {{\theta }_{C}})}\]
Correct Answer: A
Solution :
\[\mu =\frac{{{\mu }_{R}}}{{{\mu }_{D}}}=\frac{\sin {{i}_{c}}}{\sin {{90}^{o}}}\] \[\frac{{{\mu }_{R}}}{{{\mu }_{D}}}=\sin {{i}_{i}}\] \[\mu =\frac{{{\mu }_{R}}}{{{\mu }_{D}}}=\frac{\operatorname{sinA}}{\operatorname{sinr}}\] \[=\frac{\sin A}{\sin (90-A)}=\frac{\operatorname{sinA}}{\operatorname{sinA}}\] \[\frac{{{\mu }_{R}}}{{{\mu }_{D}}}=\tan A\] \[\tan A=\sin {{\theta }_{C}}\] \[A={{\tan }^{-1}}(sin{{\theta }_{C}})\]You need to login to perform this action.
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