A) (2 and 4) and (2 and 4)
B) (4 and 2) and (4 and 2)
C) (4 and 2) and (2 and 4)
D) (2 and 2) and (2 and 2)
Correct Answer: B
Solution :
Peroxodisulphuric acid \[{{H}_{2}}{{S}_{2}}{{O}_{8}}\]\[HO-\underset{\begin{smallmatrix} || \\ O \end{smallmatrix}}{\overset{\begin{smallmatrix} O \\ || \end{smallmatrix}}{\mathop{S}}}\,-O-O-\underset{\begin{smallmatrix} || \\ O \end{smallmatrix}}{\overset{\begin{smallmatrix} O \\ || \end{smallmatrix}}{\mathop{S}}}\,-OH\] Pyrosulphuric acid \[{{H}_{2}}{{S}_{2}}{{O}_{7}}:\] \[HO-\underset{\begin{smallmatrix} || \\ O \end{smallmatrix}}{\overset{\begin{smallmatrix} O \\ || \end{smallmatrix}}{\mathop{S}}}\,-O-\underset{\begin{smallmatrix} || \\ O \end{smallmatrix}}{\overset{\begin{smallmatrix} O \\ || \end{smallmatrix}}{\mathop{S}}}\,-OH\]You need to login to perform this action.
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