A) \[2x+y-9=0\text{ }~\]
B) \[x-2y+1=0\]
C) \[5x - 2y = 0\]
D) \[2x - 5y = 0\]
Correct Answer: D
Solution :
Equation of RQ is \[x -2y = 2\] ...(1) at y = 0, x = 2 [R (2, 0)] as PQ is parallel to x, y-coordinates of Q is also 3 Putting value of y in equation (1), we get Q (8, 3) Centroid of \[\Delta PQR=\left( \frac{8+5+2}{3},\frac{3+3}{3} \right)=(5,2)\]Only (2x ? 5y = 0) satisfy the given co-ordinates.You need to login to perform this action.
You will be redirected in
3 sec