A) + 670 kC
B) - 670 kC
C) 680 kC
D) + 680 kC
Correct Answer: C
Solution :
Given, Electric field E = 150 N/C Total surface charge carried by earth q = ? According to Gauss?s law. \[\phi =\frac{q}{{{\in }_{0}}}=EA\]or\[q={{\in }_{0}}EA\] \[={{\in }_{0}}E\pi {{r}^{2}}.\] \[=8.85\times {{10}^{-12}}\times 150\times {{(6.37\times {{10}^{6}})}^{2}}.\] \[\simeq 680Kc\] As electric field directed inward hence q = ? 680 KcYou need to login to perform this action.
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