JEE Main & Advanced JEE Main Paper (Held On 9 April 2014)

  • question_answer
    Van der Waal's equation for a gas is stated as, \[p=\frac{nRT}{V-nb}-a{{\left( \frac{n}{V} \right)}^{2}}.\] This equation reduces to the perfect gas equation,\[p=\frac{nRT}{V}\]when,   [JEE Main Online Paper ( Held On 09 Apirl  2014  )

    A) temperature is sufficient high and pressure is low.

    B) temperature is sufficient low and pressure is high.

    C) both temperature and pressure are very high.

    D) both temperature and pressure are very low.

    Correct Answer: D

    Solution :

                    Given\[P=\frac{nRT}{v-nb}-a{{\left( \frac{n}{v} \right)}^{2}}\] Which can also be written as \[\left[ P+\frac{{{n}^{2}}a}{{{V}^{2}}} \right](V-ab)=nRT\] At low pressure and high temperature the effect of\[\frac{a}{{{V}^{2}}}\]and b is negligible hence PV = nRT.


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