A) 15 N
B) 22.5 N
C) 33.7 N
D) 45 N
Correct Answer: A
Solution :
For 1 m length of horizontal tube Mass of water M = density × volume \[={{10}^{3}}\times \text{area}\times \text{length}\] \[={{10}^{3}}\times {{10}^{-2}}\times 1=10\,\text{kg}\] Therefore minimum force\[=\frac{\Delta p}{\Delta t}\](rate of change of momentum)= 10 × 1.5 = 15 NYou need to login to perform this action.
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