A) + 11.2
B) - 11.2
C) 8.8
D) + 8.8
Correct Answer: D
Solution :
Given, Focal length of objective, \[{{f}_{0}}=30cm\] focal length of eye lens, \[{{f}_{e}}=3.0cm\] Magnifying power, M = ? Magnifying power of the Galilean telescope, \[{{M}_{D}}=\frac{{{f}_{0}}}{{{f}_{e}}}\left( 1-\frac{{{f}_{e}}}{D} \right)\] \[=\frac{30}{3}\left( 1-\frac{3}{25} \right)\] \[[\because D=25\,cm]\] \[=10\times \frac{22}{25}=8.8cm\]You need to login to perform this action.
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