A) 1.0
B) 3.0
C) 0.5
D) 0.25
Correct Answer: A
Solution :
\[HI\frac{1}{2}{{H}_{2}}+\frac{1}{2}{{I}_{2}}\] at t = 0 at eq. \[(10.5)(0.5)(0.5)\]\[\left( \because \alpha =\frac{50}{100}=0.5 \right)\] Now\[{{K}_{C}}=\frac{{{\left( 0.5 \right)}^{1/2}}{{\left( 0.5 \right)}^{1/2}}}{0.5}=1\] \[=\frac{-13.6\times 9}{4}=-30.6eV\]You need to login to perform this action.
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