A) 300 K
B) 600 K
C) 1200 K
D) 2400 K
Correct Answer: D
Solution :
\[{{V}_{rms}}=\sqrt{\frac{3RT}{M}}\] \[{{V}_{rms({{O}_{2}})}}={{V}_{rms(He)}}\] \[\sqrt{\frac{3R{{T}_{{{O}_{2}}}}}{{{M}_{{{O}_{2}}}}}}=\sqrt{\frac{3R{{T}_{He}}}{{{M}_{He}}}}\]or\[\frac{{{T}_{{{O}_{2}}}}}{{{M}_{{{O}_{2}}}}}=\frac{{{T}_{He}}}{{{M}_{He}}}\] \[\therefore \]\[{{T}_{{{O}_{2}}}}=\frac{300\times 32}{4}=2400K\]You need to login to perform this action.
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