A) \[(-C{{H}_{2}}-\overset{\begin{smallmatrix} C{{H}_{3}} \\ | \end{smallmatrix}}{\mathop{C}}\,=CH-C{{H}_{2}}-)n\]
B) \[(-C{{H}_{2}}-CH=CH-C{{H}_{2}}-\underset{\begin{smallmatrix} | \\ {{C}_{6}}{{H}_{5}} \end{smallmatrix}}{\mathop{CH}}\,-C{{H}_{2}}\overline{n})\]
C) \[(-C{{H}_{2}}-CH=CH-C{{H}_{2}}-\underset{\begin{smallmatrix} | \\ CN \end{smallmatrix}}{\mathop{CH}}\,-C{{H}_{2}}-)n\]
D) \[{{(-C{{H}_{2}}-\overset{\begin{smallmatrix} Cl \\ | \end{smallmatrix}}{\mathop{C}}\,=CH-C{{H}_{2}}-)}_{n}}\]
Correct Answer: B
Solution :
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