A) 17
B) 7
C) 5
D) 1
Correct Answer: C
Solution :
Given \[|2\vec{a}-\vec{b}|=5\] \[\sqrt{{{(2|\vec{a}|)}^{2}}+|\vec{b}{{|}^{2}}-2\times |2\vec{a}||\vec{b}|\cos \theta }=5\] Putting values of \[|\vec{a}|\]and \[|\vec{b}|,\]we get \[{{(2\times 2)}^{2}}+{{(3)}^{2}}-24\cos \theta =25\] \[\Rightarrow \]\[\cos \theta =0\]\[\Rightarrow \]\[\theta =\frac{\pi }{2}\] \[|2\vec{a}+\vec{b}|=\sqrt{16+9+24\cos \theta }=\sqrt{25}=5\]You need to login to perform this action.
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