A) \[{{t}_{1}}=3{{t}_{2}}\]
B) \[{{t}_{1}}={{t}_{2}}\]
C) \[{{t}_{1}}=2{{t}_{2}}\]
D) \[{{t}_{1}}=4{{t}_{2}}\]
Correct Answer: A
Solution :
Total area = A Area of sabc\[=\frac{3A}{4}\] Area of sadc \[=\frac{A}{4}\] \[=\frac{3A}{4{{t}_{1}}}=\frac{A}{4{{t}_{2}}}\Rightarrow {{t}_{1}}=3{{t}_{2}}\]You need to login to perform this action.
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