A) \[5\,m{{s}^{-1}}\]
B) \[20\,m{{s}^{-1}}\]
C) \[10\,m{{s}^{-1}}\]
D) \[15\,m{{s}^{-1}}\]
Correct Answer: D
Solution :
While going up\[(\sin \theta =\tan \theta =\frac{1}{10})\] \[W\sin \theta 10+\frac{W}{20}10=P\] \[\frac{3W}{2}=P\] While going down \[\frac{W}{20}v=\frac{P}{2}=\frac{3W}{4}\] \[v=15m/s\]You need to login to perform this action.
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