JEE Main & Advanced JEE Main Paper (Held On 9 April 2016)

  • question_answer
    An experiment is performed to determine the I - V characteristics of a Zener diode, which has a protective resistance of \[R=100\Omega ,\]and maximum power of dissipation rating of 1W. The minimum voltage range of the DC source in the circuit is :   JEE Main Online Paper (Held On 09 April 2016)

    A) \[0.12V\]                 

    B) \[0.5V\]

    C) \[0.24\]

    D) \[0 . 8V\]

    Correct Answer: C

    Solution :

    \[{{P}_{zener}}=(v-100i)i=1\] \[vi-100{{i}^{2}}=1\]i must be real \[{{v}^{2}}-4(100)\ge 0\] \[v\ge 20\]                                


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