A) \[{{M}^{-1}}{{L}^{-3}}{{T}^{3}}{{I}^{2}}\]
B) \[{{M}^{-1}}{{L}^{3}}{{T}^{3}}I\]
C) \[M{{L}^{-3}}{{T}^{-3}}{{I}^{2}}\]
D) \[{{M}^{-1}}{{L}^{-3}}{{T}^{3}}I\]
Correct Answer: A
Solution :
\[J=\sigma E\] \[\sigma =\frac{J}{E}=\frac{{{I}^{1}}{{L}^{-2}}}{\frac{{{M}^{1}}{{L}^{1}}{{T}^{-2}}}{{{I}^{1}}{{T}^{1}}}}\] \[\sigma ={{M}^{-1}}{{L}^{-3}}{{T}^{3}}{{I}^{2}}\]
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