A) \[2x+2y=1-\sqrt{6}\]
B) \[x=y=3-3\sqrt{6}\]
C) \[x+y=2-\sqrt{6}\]
D) \[x+y=3-2\sqrt{6}\]
Correct Answer: D
Solution :
Slopes of x . y = 4 \[\Rightarrow \]\[\tan \theta =1\]\[\Rightarrow \]\[\left( \sin \theta =\frac{1}{\sqrt{2}},\cos \theta =\frac{1}{\sqrt{2}} \right)\] or\[\left( \sin \theta =\frac{1}{\sqrt{2},}\cos \theta =-\frac{1}{\sqrt{2}} \right)\] Q is \[\left( 2+2\sqrt{3}\left( -\frac{1}{\sqrt{2}} \right),1+2\sqrt{3}\left( -\frac{1}{\sqrt{2}} \right) \right)\] \[(2-\sqrt{6},1-\sqrt{6})\] equation of required line is \[x+y=3-2\sqrt{6}\]
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