A) 0.01 cm
B) 0.1 cm
C) 0.5 cm
D) 1 cm
Correct Answer: B
Solution :
\[T\propto \sqrt{l}\] \[l=1\] \[\frac{\Delta T}{l}\,=\frac{1}{2}\,\,\frac{\Delta l}{l}\,\,\,\,\,\,\,\,\,\,\,\,\,\Delta l={{r}_{1}}-{{r}_{2}}\] \[5\times {{10}^{-4}}\,=\frac{1}{2}\,\frac{{{r}_{1}}-{{r}_{2}}}{1}\] \[{{r}_{1}}-{{r}_{2}}\,=10\times {{10}^{-4}}\] \[{{10}^{-3}}\,m={{10}^{-1}}\,cm\,=0.1\,cm\]You need to login to perform this action.
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