A) \[{{H}_{2}}{{S}_{2}}{{O}_{7}}>{{H}_{2}}S{{O}_{3}}>{{H}_{2}}S{{O}_{4}}\]
B) \[{{H}_{2}}{{S}_{2}}{{O}_{7}}>{{H}_{2}}S{{O}_{4}}>{{H}_{2}}S{{O}_{3}}\]
C) \[{{H}_{2}}S{{O}_{4}}>{{H}_{2}}{{S}_{2}}{{O}_{7}}>{{H}_{2}}S{{O}_{3}}\]
D) \[{{H}_{2}}S{{O}_{3}}>{{H}_{2}}S{{O}_{4}}>{{H}_{2}}{{S}_{2}}{{O}_{7}}\]
Correct Answer: B
Solution :
\[{{H}_{2}}{{S}_{2}}{{O}_{7}}=HO-\underset{\begin{smallmatrix} \,|| \\ O \end{smallmatrix}}{\mathop{\overset{\begin{smallmatrix} O \\ \,|| \end{smallmatrix}}{\mathop{S}}\,}}\,-O-\underset{\begin{smallmatrix} \,|| \\ O \end{smallmatrix}}{\mathop{\overset{\begin{smallmatrix} O \\ \,|| \end{smallmatrix}}{\mathop{S}}\,}}\,-OH\] \[{{H}_{2}}S{{O}_{4}}=HO-\underset{\begin{smallmatrix} \,|| \\ O \end{smallmatrix}}{\mathop{\overset{\begin{smallmatrix} O \\ \,|| \end{smallmatrix}}{\mathop{S}}\,}}\,-OH\]You need to login to perform this action.
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