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JEE Main & Advanced JEE Main Paper (Held On 9 April 2017)

  • question_answer
    A standing wave is formed by the superposition of two waves travelling in opposite directions. The transverse displacement is given by\[y\,(x,\,t)\,=0.5\,\sin \,\left( \frac{5\pi }{4}x \right)\,\cos \,(2\text{oo}\,\pi t)\]. What is the speed of the travelling wave moving in the positive x direction? (x and t are in meter and second, respectively.) [JEE Online 09-04-2017]

    A)  120 m/s                              

    B)  90 m/s

    C)  160 m/s                              

    D)  180 m/s

    Correct Answer: C

    Solution :

                    \[V=\frac{w}{k}\] \[=\frac{200\pi }{5\pi /4}\,=160\]


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