A) \[-\frac{1}{2}\]
B) 0
C) - 1
D) \[\frac{1}{2}\]
Correct Answer: A
Solution :
\[\sin \left[ \frac{{{\cot }^{-1}}\,(1+x)}{\lambda } \right]\,=\cos \left( \frac{{{\tan }^{-1}}x}{\beta } \right)\] \[\frac{1}{\sqrt{{{x}^{2}}+2x+2}}\,\] \[=\frac{1}{1\sqrt{1+{{x}^{2}}}}\] \[{{x}^{2}}+2x+2\] \[={{x}^{2}}+1\] \[\]You need to login to perform this action.
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