A) \[53.6\,kJ\,mo{{l}^{-1}}\]
B) \[214.4\,\,kJ\,mo{{l}^{-1}}\]
C) \[107.2\,kJ\,mo{{l}^{-1}}\]
D) \[26.8\,kJ\,mo{{l}^{-1}}\]
Correct Answer: C
Solution :
\[4=\,{{e}^{\frac{Ea}{R}\left\{ \frac{1}{300}-\frac{1}{310} \right\}}}\] \[\ln \,(4)=\frac{Ea}{R}\left\{ \frac{10}{300\,\times 310} \right\}\] \[Ea\,=\frac{0.693\,\times 2\times 8.314\,\times 300\,\times 310}{10}\] \[=107165.79\,J\,=107.\,165\,kJ\]
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