JEE Main & Advanced JEE Main Paper Phase-I (Held on 07-1-2020 Evening)

  • question_answer
    An elevator in a building can carry a maximum of 10 persons, with the average mass of each person being 68 kg. The mass of the elevator itself is 920 kg and it moves with a constant speed of 3 m/s. The frictional force opposing the motion is 6000 N. If the elevator is moving up with its full capacity, the power delivered by the motor to the elevator \[(g=10\text{ }m/{{s}^{2}})\]must be at least  [JEE MAIN Held on 07-01-2020 Evening]

    A) 56300 W                     

    B) 66000 W

    C) 48000 W         

    D) 62360 W

    Correct Answer: B

    Solution :

    [b] \[F=(10\text{ }m+M)g+f\] where, m = 68 kg, M = 920 kg, f = 6000 N \[\Rightarrow \,\,\,\,\,F=22000\text{ }N\] \[\Rightarrow \,\,\,\,\,P=FV=22000\times 3=66000\text{ }W\]

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