JEE Main & Advanced JEE Main Paper Phase-I (Held on 07-1-2020 Evening)

  • question_answer
    The dimension of \[\frac{{{B}^{2}}}{2{{\mu }_{0}}},\] where B is magnetic field and \[{{\mu }_{0}}\] is the magnetic permeability of vaccum, is [JEE MAIN Held on 07-01-2020 Evening]

    A) \[M{{L}^{1}}\text{ }{{T}^{\,2}}\]

    B) \[M{{L}^{2}}\text{ }{{T}^{\,\,2}}\]

    C) \[M{{L}^{2}}\text{ }{{T}^{\,\,1}}\]

    D) \[ML{{T}^{\,2}}\]

    Correct Answer: A

    Solution :

    [a] The quantity \[\frac{{{B}^{2}}}{2{{\mu }_{0}}}\] is the energy density of magnetic field. \[\Rightarrow \,\,\,\left[ \frac{{{B}^{2}}}{2\,{{\mu }_{0}}} \right]=\left[ \frac{M{{L}^{2}}{{T}^{-2}}}{{{L}^{3}}} \right]\,=M{{L}^{-1}}{{T}^{-2}}\]

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