JEE Main & Advanced JEE Main Paper Phase-I (Held on 07-1-2020 Evening)

  • question_answer
    For the following reactions where, \[{{k}_{s}}\] and \[{{k}_{e}}\], are, respectively, the rate constants for substitution and elimination, and \[\mu =\frac{{{k}_{s}}}{{{k}_{e}}}\]the correct option is _________ .  [JEE MAIN Held on 07-01-2020 Evening]

    A) \[{{\mu }_{B}}>{{\mu }_{A}}\] and \[{{k}_{e}}(A)>{{k}_{e}}(B)\]

    B) \[{{\mu }_{A}}>{{\mu }_{B}}\] and \[{{k}_{e}}(A)>{{k}_{e}}(B)\]

    C) \[{{\mu }_{B}}>{{\mu }_{A}}\] and \[{{k}_{e}}(A)>{{k}_{e}}(B)\]

    D) \[{{\mu }_{A}}>{{\mu }_{B}}\] and \[{{k}_{e}}(A)>{{k}_{e}}(B)\]

    Correct Answer: D

    Solution :

    [d]             when \[{{Z}^{\Theta }}=C{{H}_{3}}C{{H}_{2}}{{O}^{-}}(A)\]             \[\Rightarrow \,\,{{\mu }_{A}}>{{\mu }_{B}}\] and \[{{k}_{e}}(B)\,>\,{{k}_{e}}(A)\]

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