A) 3.9 mm
B) 6.9 mm
C) 5.9 mm
D) 4.9 mm
Correct Answer: C
Solution :
[c] Fringe-width, \[\omega =\frac{D}{d}\,\lambda =\frac{1.5}{0.15\times {{10}^{-3}}}\times 589\times {{10}^{-9}}\,m\] \[=589\times {{10}^{\,2}}\text{ }mm=5.89\text{ }mm\] \[~\approx 5.9\text{ }mm\]
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