JEE Main & Advanced JEE Main Paper Phase-I (Held on 07-1-2020 Evening)

  • question_answer
    The equation that is incorrect is                                     [JEE MAIN Held on 07-01-2020 Evening]

    A) \[{{(\Lambda _{m}^{{}^\circ })}_{NaBr}}-(\Lambda _{m}^{{}^\circ }){{\,}_{NaCl}}={{(\Lambda _{m}^{{}^\circ })}_{kBr}}-{{(\Lambda _{m}^{{}^\circ })}_{KCl}}\]

    B) \[{{(\Lambda _{m}^{{}^\circ })}_{{{H}_{2}}O}}={{(\Lambda _{m}^{{}^\circ })}_{\,HCl}}+{{(\Lambda _{m}^{{}^\circ })}_{NaO{{H}^{-}}}}{{(\Lambda _{m}^{{}^\circ })}_{NaCl}}\]

    C) \[{{(\Lambda _{m}^{{}^\circ })}_{NaBr}}-(\Lambda _{m}^{{}^\circ }){{\,}_{NaI}}={{(\Lambda _{m}^{{}^\circ })}_{kBr}}-{{(\Lambda _{m}^{{}^\circ })}_{NaBr}}\]

    D) \[{{(\Lambda _{m}^{{}^\circ })}_{KCl}}-(\Lambda _{m}^{{}^\circ }){{\,}_{NaCl}}={{(\Lambda _{m}^{{}^\circ })}_{kBr}}-{{(\Lambda _{m}^{{}^\circ })}_{NaBr}}\]

    Correct Answer: C

    Solution :

    [c] \[\Lambda _{m}^{{}^\circ }NaBr-\Lambda _{m}^{{}^\circ }NaI=\Lambda _{m}^{{}^\circ }(B{{r}^{-}})-\Lambda _{m}^{{}^\circ }({{I}^{-}})\] .......(1)
    \[\Lambda _{m}^{{}^\circ }(KBr)-\Lambda _{m}^{{}^\circ }(NaBr)=\Lambda _{m}^{{}^\circ }({{K}^{+}})-\Lambda _{m}^{{}^\circ }(N{{a}^{+}})\] .....(2)
    (1) and (2) are not equal.

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