• # question_answer The equation that is incorrect is                                     [JEE MAIN Held on 07-01-2020 Evening] A) ${{(\Lambda _{m}^{{}^\circ })}_{NaBr}}-(\Lambda _{m}^{{}^\circ }){{\,}_{NaCl}}={{(\Lambda _{m}^{{}^\circ })}_{kBr}}-{{(\Lambda _{m}^{{}^\circ })}_{KCl}}$ B) ${{(\Lambda _{m}^{{}^\circ })}_{{{H}_{2}}O}}={{(\Lambda _{m}^{{}^\circ })}_{\,HCl}}+{{(\Lambda _{m}^{{}^\circ })}_{NaO{{H}^{-}}}}{{(\Lambda _{m}^{{}^\circ })}_{NaCl}}$ C) ${{(\Lambda _{m}^{{}^\circ })}_{NaBr}}-(\Lambda _{m}^{{}^\circ }){{\,}_{NaI}}={{(\Lambda _{m}^{{}^\circ })}_{kBr}}-{{(\Lambda _{m}^{{}^\circ })}_{NaBr}}$ D) ${{(\Lambda _{m}^{{}^\circ })}_{KCl}}-(\Lambda _{m}^{{}^\circ }){{\,}_{NaCl}}={{(\Lambda _{m}^{{}^\circ })}_{kBr}}-{{(\Lambda _{m}^{{}^\circ })}_{NaBr}}$

 [c] $\Lambda _{m}^{{}^\circ }NaBr-\Lambda _{m}^{{}^\circ }NaI=\Lambda _{m}^{{}^\circ }(B{{r}^{-}})-\Lambda _{m}^{{}^\circ }({{I}^{-}})$ .......(1) $\Lambda _{m}^{{}^\circ }(KBr)-\Lambda _{m}^{{}^\circ }(NaBr)=\Lambda _{m}^{{}^\circ }({{K}^{+}})-\Lambda _{m}^{{}^\circ }(N{{a}^{+}})$ .....(2) (1) and (2) are not equal.