question_answer

The ammonia \[(N{{H}_{3}})\]released on quantitative reaction of 0.6 g urea \[(N{{H}_{2}}CON{{H}_{2}})\]with sodium hydroxide (NaOH) can be neutralized by [JEE MAIN Held on 07-01-2020 Evening]

A) 200 ml of 0.4 N HCl

B) 100 ml of 0.1 N HCl

C) 200 ml of 0.2 N HCl

D) 100 ml of 0.2 N HCl

Correct Answer: D

Solution :

[d]             2 moles of \[N{{H}_{3}}\]will react with 2 mole of HCl. 0.6 g of urea give \[=\frac{0.6}{60}\times 2\,=0.02\]mol of \[N{{H}_{3}}\] \[100\times 0.2\text{ }N\text{ }HCl=0.02\text{ }mol\] of HCl